Evaluate $L = 2 C + 1.57 ( D + d ) + \frac { ( D - d ) ^ { 2 } } { 4 C }$ if $C = 28$ in., $D = 18$ in., and $d = 8$ in. This is the formula that finds the length of a belt that goes around two pulleys.
A)L = 97.71 in.
B)L = 102.86 in.
C)L = 96.91 in.
D)L = 64.5 in.

Question

Quizplus · Accepted Answer

Plugging the given values into the formula $L = 2C + 1.57(D + d) + \frac{(D - d)^2}{4C}$, we get $L = 2(28) + 1.57(18 + 8) + \frac{(18 - 8)^2}{4(28)} = 56 + 1.57(26) + \frac{100}{112} = 56 + 40.82 + 0.89 = 97.71$ inches.

Evaluate L=2C+1.57(D+d)+(D−d)24CL = 2 C + 1.57 ( D + d ) + \frac { ( D - d ) ^ { 2 } } { 4 C }L=2C+1.57(D+d)+4C(D−d)2​

Evaluate $L = 2 C + 1.57 ( D + d ) + \frac { ( D - d ) ^ { 2 } } { 4 C }$