Event 3A
Given the following event:
Given two urns, one containing 2 green, 3 yellow, and 5 pink balls, and the other containing 4 green, 2 yellow, and 4 pink balls. A single ball is drawn from each.
-Given Event 3A, what is the probability that one is green, the other is pink?
A) 1/4
B) 2/3
C) 8/25
D) 47/50
E) 7/25

Question

Quizplus · Accepted Answer

The probability of drawing one green and one pink ball from the two urns involves calculating the probability of drawing a green ball from one urn and a pink ball from the other, and vice versa, then adding these probabilities together.First, calculate the probability of drawing a green ball from the first urn and a pink ball from the second urn. The probability of drawing a green ball from the first urn is 2/10 (since there are 2 green balls out of a total of 10 balls). The probability of drawing a pink ball from the second urn is 4/10 (since there are 4 pink balls out of a total of 10 balls). So, the probability of this combination is (2/10) * (4/10) = 8/100.Next, calculate the probability of drawing a pink ball from the first urn and a green ball from the second urn. The probability of drawing a pink ball from the first urn is 5/10, and the probability of drawing a green ball from the second urn is 4/10. So, the probability of this combination is (5/10) * (4/10) = 20/100.Adding these probabilities together gives (8/100) + (20/100) = 28/100, which simplifies to 7/25.

Event 3A Given the Following Event