Given an urn containing 4 green balls and 5 orange balls. If two balls are drawn and the first ball is not replaced before the second is drawn, what is the probability that both balls are green?
A) 7/18
B) 1/6
C) 4/27
D) 7/17
E) 16/81

Question

Quizplus · Accepted Answer

The probability of drawing the first green ball is 4/9. After drawing one green ball, there are 3 green balls left out of a total of 8 balls. The probability of drawing a second green ball is 3/8. Thus, the probability of both events occurring is (4/9) * (3/8) = 1/6.

Given an Urn Containing 4 Green Balls and 5 Orange