Identify the conic as a circle or an ellipse then find the radius for circle or center for ellipse. $\frac { x ^ { 2 } } { 4 / 49 } + \frac { ( y + 1 ) ^ { 2 } } { 4 / 49 } = 1$
A)EllipseCenter: $\frac { 2 } { 7 }$
B)EllipseCenter: 1
C)CircleRadius: 1
D)CircleRadius: $\frac { 2 } { 7 }$
E)None of the above

Question

Identify the conic as a circle or an ellipse then find the radius for circle or center for ellipse.  $\frac { x ^ { 2 } } { 4 / 49 } + \frac { ( y + 1 ) ^ { 2 } } { 4 / 49 } = 1$ 
A)EllipseCenter: $\frac { 2 } { 7 }$
B)EllipseCenter: 1
C)CircleRadius: 1
D)CircleRadius: $\frac { 2 } { 7 }$
E)None of the above

Quizplus · Accepted Answer

The given equation is of a circle because the coefficients of $x^2$ and $y^2$ are equal, indicating a circle. The radius can be found by taking the square root of the denominator under $x^2$ and $y^2$, which is $\sqrt{4/49} = 2/7$.

Identify the Conic as a Circle or an Ellipse Then x24/49+(y+1)24/49=1\frac { x ^ { 2 } } { 4 / 49 } + \frac { ( y + 1 ) ^ { 2 } } { 4 / 49 } = 14/49x2​+4/49(y+1)2​=1

Identify the Conic as a Circle or an Ellipse Then $\frac { x ^ { 2 } } { 4 / 49 } + \frac { ( y + 1 ) ^ { 2 } } { 4 / 49 } = 1$