Find the vertices of the conic. $\frac { x ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 36 } = 1$
A)Vertices: $( 0 , \pm 3 )$
B)Vertices: $( \pm 6,0 )$
C)Vertices: $( 0 , \pm 6 )$
D)Vertices: $( \pm 3,6 )$
E)Vertices: $( \pm 3,0 )$

Question

Find the vertices of the conic.  $\frac { x ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 36 } = 1$ 
A)Vertices: $( 0 , \pm 3 )$
B)Vertices: $( \pm 6,0 )$
C)Vertices: $( 0 , \pm 6 )$
D)Vertices: $( \pm 3,6 )$
E)Vertices: $( \pm 3,0 )$

Quizplus · Accepted Answer

The given equation is of an ellipse centered at the origin with a vertical major axis. The vertices are at $(0, \pm b)$ where $b = \sqrt{36} = 6$.

Find the Vertices of the Conic x29+y236=1\frac { x ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 36 } = 19x2​+36y2​=1

Find the Vertices of the Conic $\frac { x ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 36 } = 1$