Find the probability for the experiment of tossing a six-sided die twice such that the sum is either 7 or 11.
A) $\frac { 2 } { 9 }$
B) $\frac { 1 } { 3 }$
C) $\frac { 1 } { 6 }$
D) $\frac { 5 } { 16 }$
E) $\frac { 7 } { 36 }$

Question

Find the probability for the experiment of tossing a six-sided die twice such that the sum is either 7 or 11.  
A) $\frac { 2 } { 9 }$
B) $\frac { 1 } { 3 }$
C) $\frac { 1 } { 6 }$
D) $\frac { 5 } { 16 }$
E) $\frac { 7 } { 36 }$

Quizplus · Accepted Answer

The sum of 7 can be obtained in 6 ways: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1). The sum of 11 can be obtained in 2 ways: (5, 6), (6, 5). So, the total number of ways to get a sum of 7 or 11 is 6 + 2 = 8. The total number of possible outcomes when a die is tossed twice is 6 * 6 = 36. Therefore, the probability of getting a sum of 7 or 11 is 8/36 = 2/9.

Find the Probability for the Experiment of Tossing a Six-Sided 29\frac { 2 } { 9 }92​

Find the Probability for the Experiment of Tossing a Six-Sided $\frac { 2 } { 9 }$