Solve the system. $\left\{ \begin{array} { l }
12 x - 28 y = 12 \
- 6 x + 14 y = - 6
\end{array} \right.$
A)x = 3, y = 7
B)x = 4, y = 3
C) $\left( x , \frac { 3 x } { 7 } - \frac { 3 } { 7 } \right)$
D)x = 2, y = 3
E)No solution

Question

Solve the system.  $\left\{ \begin{array} { l } 
12 x - 28 y = 12 \
- 6 x + 14 y = - 6
\end{array} \right.$  
A)x = 3, y = 7
B)x = 4, y = 3
C) $\left( x , \frac { 3 x } { 7 } - \frac { 3 } { 7 } \right)$
D)x = 2, y = 3
E)No solution

Quizplus · Accepted Answer

The second equation is exactly half of the first, indicating that they are not independent equations but the same line represented differently. Therefore, there are infinitely many solutions along this line, which can be represented parametrically as shown in option C.

Solve the System {12x−28y=12−6x+14y=−6\left\{ \begin{array} { l } 12 x - 28 y = 12 \\- 6 x + 14 y = - 6\end{array} \right.{12x−28y=12−6x+14y=−6​

Solve the System $\left\{ \begin{array} { l } 12 x - 28 y = 12 \\- 6 x + 14 y = - 6\end{array} \right.$