Solve the system by the method of substitution. $\left\{ \begin{aligned}
- \frac { 2 } { 3 } x + y & = 8 \
2 x - 3 y & = 20
\end{aligned} \right.$
A)(-20, -40)
B)No solution
C)(20, 40)
D) $\left( - \frac { 20 } { 3 } , \frac { 40 } { 3 } \right)$
E) $\left( \frac { 20 } { 3 } , \frac { 40 } { 3 } \right)$

Question

Solve the system by the method of substitution.  $\left\{ \begin{aligned}
- \frac { 2 } { 3 } x + y & = 8 \
2 x - 3 y & = 20
\end{aligned} \right.$  
A)(-20, -40)
B)No solution
C)(20, 40)
D) $\left( - \frac { 20 } { 3 } , \frac { 40 } { 3 } \right)$
E) $\left( \frac { 20 } { 3 } , \frac { 40 } { 3 } \right)$

Quizplus · Accepted Answer

The Answer of Solve the system by the method of substitution.  $\left\{ \begin{aligned}
- \frac { 2 } { 3 } x + y & = 8 \
2 x - 3 y & = 20
\end{aligned} \right.$  
A)(-20, -40)
B)No solution
C)(20, 40)
D) $\left( - \frac { 20 } { 3 } , \frac { 40 } { 3 } \right)$
E) $\left( \frac { 20 } { 3 } , \frac { 40 } { 3 } \right)$

Solve the System by the Method of Substitution {−23x+y=82x−3y=20\left\{ \begin{aligned}- \frac { 2 } { 3 } x + y & = 8 \\2 x - 3 y & = 20\end{aligned} \right.⎩⎨⎧​−32​x+y2x−3y​=8=20​

Solve the System by the Method of Substitution $\left\{ \begin{aligned}- \frac { 2 } { 3 } x + y & = 8 \\2 x - 3 y & = 20\end{aligned} \right.$