Solve the system of linear equations. $$\left\{ \begin{array} { l l }
- 2 x + 3 y - 4 z & = - 19 \
4 x - y - z & = 22 \
4 x + y - z & = 12
\end{array} \right.$$
A) $( 1 , - 4 , - 4 )$
B) $( 4 , - 5 , - 1 )$
C) $( - 5 , - 1,4 )$
D)inconsistent
E) $( - 4,1 , - 4 )$

Question

Solve the system of linear equations.  $$\left\{ \begin{array} { l l } 
- 2 x + 3 y - 4 z & = - 19 \
4 x - y - z & = 22 \
4 x + y - z & = 12
\end{array} \right.$$
A)  $( 1 , - 4 , - 4 )$
B)  $( 4 , - 5 , - 1 )$
C)  $( - 5 , - 1,4 )$
D)inconsistent
E)  $( - 4,1 , - 4 )$

Quizplus · Accepted Answer

By solving the system of equations using substitution or elimination, the solution is found to be $( 4 , - 5 , - 1 )$.

Solve the System of Linear Equations {−2x+3y−4z=−194x−y−z=224x+y−z=12\left\{ \begin{array} { l l } - 2 x + 3 y - 4 z & = - 19 \\4 x - y - z & = 22 \\4 x + y - z & = 12\end{array} \right.⎩⎨⎧​−2x+3y−4z4x−y−z4x+y−z​=−19=22=12​

Solve the System of Linear Equations $\left\{ \begin{array} { l l } - 2 x + 3 y - 4 z & = - 19 \\4 x - y - z & = 22 \\4 x + y - z & = 12\end{array} \right.$