Solve the system of linear equations. $$\left\{ \begin{array} { c c c }
x + y + z & = 2 \
x - y + 2 z & = - 13 \
- 4 y - z & = - 33
\end{array} \right.$$
A) $( - 7,8,1 )$
B) $( 8 , - 7,1 )$
C) $( 7 , - 8,3 )$
D) $( - 8,7,3 )$
E) $( - 4,6,0 )$

Question

Solve the system of linear equations.  $$\left\{ \begin{array} { c c c } 
x + y + z & = 2 \
x - y + 2 z & = - 13 \
- 4 y - z & = - 33
\end{array} \right.$$
A)  $( - 7,8,1 )$
B)  $( 8 , - 7,1 )$
C)  $( 7 , - 8,3 )$
D)  $( - 8,7,3 )$
E)  $( - 4,6,0 )$

Quizplus · Accepted Answer

Solving the system of equations by substitution or elimination, we find that $x = -7$, $y = 8$, and $z = 1$, which corresponds to choice A $(-7, 8, 1)$.

Solve the System of Linear Equations {x+y+z=2x−y+2z=−13−4y−z=−33\left\{ \begin{array} { c c c } x + y + z & = 2 \\x - y + 2 z & = - 13 \\- 4 y - z & = - 33\end{array} \right.⎩⎨⎧​x+y+zx−y+2z−4y−z​=2=−13=−33​

Solve the System of Linear Equations $\left\{ \begin{array} { c c c } x + y + z & = 2 \\x - y + 2 z & = - 13 \\- 4 y - z & = - 33\end{array} \right.$