Solve the equation algebraically.Round the result to three decimal places. $\frac { 3 + \ln x } { 8 } = 0$
A) $e ^ { - 3 } \approx 2,980.958$
B) $e ^ { - 3 } \approx 0$
C) $e ^ { - 3 } \approx 54.598$
D) $e ^ { - 3 } \approx 0.050$
E) $e ^ { - 3 } \approx 20.086$

Question

Solve the equation algebraically.Round the result to three decimal places.  $\frac { 3 + \ln x } { 8 } = 0$ 
A) $e ^ { - 3 } \approx 2,980.958$
B) $e ^ { - 3 } \approx 0$
C) $e ^ { - 3 } \approx 54.598$
D) $e ^ { - 3 } \approx 0.050$
E) $e ^ { - 3 } \approx 20.086$

Quizplus · Accepted Answer

First, isolate $\ln x$ by multiplying both sides by 8, resulting in $3 + \ln x = 0$. Then, subtract 3 from both sides to get $\ln x = -3$. To solve for $x$, exponentiate both sides with base $e$, leading to $x = e^{-3}$. Calculating $e^{-3}$ gives approximately $0.050$.

Solve the Equation Algebraically 3+ln⁡x8=0\frac { 3 + \ln x } { 8 } = 083+lnx​=0

Solve the Equation Algebraically $\frac { 3 + \ln x } { 8 } = 0$