Solve the logarithmic equation algebraically.Approximate the result to three decimal places. $\ln x = - 5$
A) $e ^ { - 5 } \approx 2.007$
B) $e ^ { - 5 } \approx 1.007$
C) $e ^ { - 5 } \approx 3.007$
D) $e ^ { - 5 } \approx - 1.993$
E) $e ^ { - 5 } \approx 0.007$

Question

Solve the logarithmic equation algebraically.Approximate the result to three decimal places.  $\ln x = - 5$ 
A) $e ^ { - 5 } \approx 2.007$
B) $e ^ { - 5 } \approx 1.007$
C) $e ^ { - 5 } \approx 3.007$
D) $e ^ { - 5 } \approx - 1.993$
E) $e ^ { - 5 } \approx 0.007$

Quizplus · Accepted Answer

The solution to $\ln x = -5$ is $x = e^{-5}$. Calculating $e^{-5}$ gives approximately 0.007.

Solve the Logarithmic Equation Algebraically ln⁡x=−5\ln x = - 5lnx=−5 A) e−5≈2.007e ^ { - 5 } \approx 2.007e−5≈2.007

Solve the Logarithmic Equation Algebraically $\ln x = - 5$ A) $e ^ { - 5 } \approx 2.007$