Use the intercept form to find the equation of the line with the given intercepts.The intercept form of the equation of a line with intercepts (a, 0) and (0, b) is $\frac { x } { a } + \frac { y } { b } = 1 , a \neq 0 , b \neq 0$
Point on line: (4, 6)
X-intercept: (c, 0)
Y-intercept: (0, c), c$\neq$ 0

A) $x + y + 10 = 0$
B) $x + y - 10 = 0$
C) $- x + y - 10 = 0$
D) $x - y - 10 = 0$
E) $- x - y - 10 = 0$

Question

Use the intercept form to find the equation of the line with the given intercepts.The intercept form of the equation of a line with intercepts (a, 0) and (0, b) is $\frac { x } { a } + \frac { y } { b } = 1 , a \neq 0 , b \neq 0$ 
 Point on line: (4, 6)
X-intercept: (c, 0)
Y-intercept: (0, c), c$\neq$ 0

A) $x + y + 10 = 0$
B) $x + y - 10 = 0$
C) $- x + y - 10 = 0$
D) $x - y - 10 = 0$
E) $- x - y - 10 = 0$

Quizplus · Accepted Answer

Given the intercepts are (c, 0) and (0, c), the intercept form equation is $\frac{x}{c} + \frac{y}{c} = 1$, which simplifies to $x + y = c$. Since the point (4, 6) lies on the line, substituting x = 4 and y = 6 gives $4 + 6 = c$, so $c = 10$. Therefore, the equation is $x + y - 10 = 0$.

Use the Intercept Form to Find the Equation of the Line