Question 1

A metallic surface is illuminated with light of wavelength 400 nm. If the work function for this metal is 2.40 eV, what is the maximum kinetic energy of the ejected electrons, in electron-volts? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

Accepted Answer

The answer of A metallic surface is illuminated with light...

Question 2

A laser pulse of duration 25 ms has a total energy of 1.4 J. If the wavelength of this radiation is 567 nm, how many photons are emitted in one pulse? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

Accepted Answer

The answer of A laser pulse of duration 25 ms...

Question 3

For what wavelength does a 100-mW laser beam deliver 1.6 × 10¹⁷ photons in one second? (c = 3.0 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

Accepted Answer

First we need to find the energy of one photon using the formula:

E = hc/λ

where h is Planck's constant, c is the speed of light, and λ is the wavelength.

Rearranging to solve for λ, we get:

λ = hc/E

Using the energy of the laser beam (100 mW = 100 x 10^-3 J/s) and the number of photons delivered in one second (1.6 x 10^20 photons/s), we can find the energy of one photon:

E = (100 x 10^-3 J/s) / (1.6 x 10^20 photons/s) = 6.25 x 10^-19 J/photon

Plugging this into the formula above, we get:

λ = (6.626 x 10^-34 J s) x (3.0 x 10^8 m/s) / (6.25 x 10^-19 J/photon) ≈ 319.7 nm

Rounding to the nearest nm, we get 320 nm. Therefore, the best choice is A.

Question 4

A metal has a work function of 4.50 eV. Find the maximum kinetic energy of the photoelectrons if light of wavelength 250 nm shines on the metal. (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

Accepted Answer

First, we need to find the energy of a photon with a wavelength of 250 nm using the formula E = hc/λ, where h is Planck's constant and c is the speed of light. 
E = (6.626 × 10^-34 J ∙ s)(3.00 × 10^8 m/s)/(250 × 10^-9 m) = 7.96 × 10^-19 J
Next, we need to find the energy required to remove an electron from the metal, which is the work function, 4.50 eV. We convert this to Joules using the conversion factor provided: 
W = 4.50 eV × 1.60 × 10^-19 J/eV = 7.20 × 10^-19 J
Now we can find the maximum kinetic energy of the photoelectrons using the formula K.E. = E - W: 
K.E. = 7.96 × 10^-19 J - 7.20 × 10^-19 J = 0.76 × 10^-19 J
Finally, we convert this to electron volts (eV) using the conversion factor provided: 
K.E. = 0.76 × 10^-19 J/1.60 × 10^-19 J/eV = 0.475 eV, which is closest to option C, 0.47 eV.

Question 5

Gamma rays are photons with very high energy. What is the wavelength of a gamma-ray photon with energy 7.7 × 10^-13 J? (c = 3.0 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

Accepted Answer

The answer of Gamma rays are photons with very high...

Question 6

A laser emits a pulse of light that lasts 10 ns. The light has a wavelength of 690 nm, and each pulse has an energy of 480 mJ. How many photons are emitted in each pulse? (c = 3.0 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

Accepted Answer

To find the number of photons, first calculate the energy of a single photon using E = hc/λ. Then, divide the total energy of the pulse by the energy of a single photon. This gives approximately 1.7 × 10^18 photons.

Question 7

An 84-kW AM radio station broadcasts at 1000 kHz. How many photons are emitted each second by the transmitting antenna? (h = 6.626 × 10^-34 J ? s)

Accepted Answer

The energy of each photon is hf, where h is Planck's constant and f is the frequency. The power of the station is the total energy emitted per second, which is the number of photons emitted per second multiplied by the energy of each photon. Therefore, the number of photons emitted per second is the power divided by the energy of each photon.$$N = \frac{P}{hf} = \frac{84 	imes 10^3 	ext{ W}}{(6.626 	imes 10^{-34} 	ext{ J s})(1000 	imes 10^3 	ext{ Hz})} = 1.3 	imes 10^{32}$$

Question 8

A metal surface has a work function of 2.50 eV. What is the longest wavelength of light that will eject electrons from the surface of this metal? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

Accepted Answer

The answer of A metal surface has a work function...

Question 9

The work function of a particular metal is $4.20 \times 10 ^ { - 19 } \mathrm {~J}$ What is the photoelectric cutoff (threshold)wavelength for this metal? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

Accepted Answer

The photoelectric cutoff wavelength is given by:$$\lambda = \frac{hc}{\phi}$$where:* h is Planck's constant* c is the speed of light* $\phi$ is the work functionPlugging in the given values, we get:$$\lambda = \frac{(6.626 	imes 10^{-34} \mathrm{~J \cdot s})(3.00 	imes 10^8 \mathrm{~m/s})}{4.20 	imes 10^{-19} \mathrm{~J}} = 473 \mathrm{~nm}$$Therefore, the correct answer is A.

Question 10

A helium-neon laser emits light at 632.8 nm. If the laser emits $1.82 \times 10 ^ { 17 }$ photons/second, what is its power output in mW? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

Accepted Answer

The energy of a single photon is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the light. The power output of the laser is the total energy emitted per second, which is equal to the number of photons emitted per second multiplied by the energy of each photon. Therefore, the power output is:P = (1.82 × 10^17 photons/second) × (6.626 × 10^-34 J ? s) × (3.00 × 10^8 m/s) / (632.8 × 10^-9 m) = 57.2 mW

Question 11

Certain planes of a crystal of halite have a spacing of 0.399 nm. The crystal is irradiated by a beam of x-rays. First order constructive interference occurs when the beam makes an angle of 20° with the planes of the crystal surface. What angle does the beam make with the crystal planes for second order constructive?

Accepted Answer

For first order constructive interference:
$d\sin	heta = \lambda$
Where
$d$ = spacing between planes of crystal surface (given) = $0.399~	ext{nm}$
$	heta$ = angle between the beam and the planes of the crystal surface (given) = $20°$
$\lambda$ = wavelength of x-ray (to be found) = ?
Solving for $\lambda$,
$\lambda = \frac{d}{\sin	heta} = \frac{0.399~	ext{nm}}{\sin 20°} = 1.16~	ext{nm}$

For second order constructive interference:
$2d\sin	heta = n\lambda$
Where
$n$ = order of interference (given) = $2$
Substituting the value of $\lambda$ from the previous calculation, we get
$2	imes0.399~	ext{nm}	imes\sin	heta = 2	imes1.16~	ext{nm}$
Solving for $	heta$,
$\sin	heta = \frac{2	imes1.16~	ext{nm}}{2	imes0.399~	ext{nm}}$
$\sin	heta = 5.80$
This is not possible as $\sin	heta$ cannot be greater than $1$.
Hence, there is no solution for second order constructive interference.
However, if we consider the approximation $\sin	heta \approx 	heta$ for small angles, we can estimate:
$	heta \approx \frac{2	imes1.16~	ext{nm}}{2	imes0.399~	ext{nm}} = 5.80$
$	heta \approx 43°$
Therefore, the answer is (C).

Question 12

A crystal is irradiated with x-rays with a wavelength of 0.120 nm. The atomic planes in the crystal are separated by 0.21 nm. At what angles of incidence with respect to the normal will the x-rays reflect from the crystal?

Accepted Answer

The answer of A crystal is irradiated with x-rays with...

Question 13

If the longest wavelength of light that is able to dislodge electrons from a metal is 373 nm, what is the work function of that metal, in electron-volts? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

Accepted Answer

The answer of If the longest wavelength of light that...

Question 14

A photoelectric surface has a work function of 2.10 eV. Calculate the maximum kinetic energy, in eV, of electrons ejected from this surface by electromagnetic radiation of wavelength 356 nm. (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

Accepted Answer

The answer of A photoelectric surface has a work function...

Question 15

What is the cutoff (threshold)frequency for a metal surface that has a work function of 5.42 eV? (1 eV = 1.60 × 10^-19 J, h = 6.626 × 10^-34 J ? s)

Accepted Answer

The cutoff frequency is calculated using the formula $ f = \frac{\phi}{h} $, where $ \phi $ is the work function in joules. Converting 5.42 eV to joules gives $ 5.42 \times 1.60 \times 10^{-19} $ J. Dividing by Planck's constant $ h = 6.626 \times 10^{-34} $ J·s gives approximately $ 1.31 \times 10^{15} $ Hz.

Question 16

The work function of a certain metal is 1.90 eV. What is the longest wavelength of light that can cause photoelectron emission from this metal? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

Accepted Answer

The answer of The work function of a certain metal...

Question 17

Gamma rays are photons with very high energy. How many visible-light photons with a wavelength of 500 nm would you need to equal the energy of a gamma-ray photon with energy $4.1 \times 10 ^ { - 13 } \mathrm {~J} ?$

Accepted Answer

The energy of a photon is given by E = hf, where h is Planck's constant and f is the frequency of the photon. The frequency of a photon is given by c/λ, where c is the speed of light and λ is the wavelength of the photon. So, the energy of a photon is given by E = hc/λ.The energy of a gamma-ray photon with energy $4.1 \times 10 ^ { - 13 } \mathrm {~J} $ is:$$E = 4.1 \times 10 ^ { - 13 } \mathrm {~J}$$The wavelength of a visible-light photon with a wavelength of 500 nm is:$$\lambda = 500 \mathrm {~nm} = 500 \times 10 ^ { - 9 } \mathrm {~m}$$The energy of a visible-light photon with a wavelength of 500 nm is:$$E = hc/\lambda = (6.626 \times 10 ^ { - 34 } \mathrm {~J \cdot s})(3 \times 10 ^ { 8 } \mathrm {~m/s})/(500 \times 10 ^ { - 9 } \mathrm {~m}) = 3.98 \times 10 ^ { - 19 } \mathrm {~J}$$The number of visible-light photons with a wavelength of 500 nm that would be needed to equal the energy of a gamma-ray photon with energy $4.1 \times 10 ^ { - 13 } \mathrm {~J} $ is:$$N = E_\gamma/E_\mathrm{visible} = (4.1 \times 10 ^ { - 13 } \mathrm {~J})/(3.98 \times 10 ^ { - 19 } \mathrm {~J}) = 1.03 \times 10 ^ { 6 }$$So, the correct answer is A.

Question 18

What is the longest wavelength of light that can cause photoelectron emission from a metal that has a work function of 2.20 eV? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

Accepted Answer

The wavelength can be found using the equation $ \lambda = \frac{hc}{E} $, where $ h $ is Planck's constant, $ c $ is the speed of light, and $ E $ is the energy in joules. First, convert the work function from eV to joules: $ 2.20 \, \text{eV} = 2.20 \times 1.60 \times 10^{-19} \, \text{J} $. Then, $ \lambda = \frac{6.626 \times 10^{-34} \times 3.00 \times 10^{8}}{2.20 \times 1.60 \times 10^{-19}} $, which calculates to approximately $ 5.65 \times 10^{-7} \, \text{m} $ or 565 nm.

Question 19

The lattice spacing of the principal Bragg planes in sodium chloride is 0.282 nm. For what wavelength of x-rays will the first order reflected beam diffract at 55° with respect to the normal to the crystal planes?

Accepted Answer

The Bragg's law equation, $n\lambda = 2d\sin(\theta)$, where $n$ is the order of reflection (here, $n=1$), $d$ is the lattice spacing (0.282 nm), and $\theta$ is the angle with respect to the normal (55°), can be used to find the wavelength $\lambda$. Substituting the given values, $\lambda = \frac{2 \times 0.282 \times \sin(55°)}{1}$, results in a wavelength of approximately 0.323 nm.

Question 20

What is the wavelength of a 6.32-eV photon? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s, 1 eV = 1.60 × 10^-19J)

Accepted Answer

The wavelength of a photon can be calculated using the formula λ = hc/E, where h is Planck's constant, c is the speed of light, and E is the energy of the photon. First, convert the energy from eV to Joules: 6.32 eV * 1.60 × 10^-19 J/eV = 1.0112 × 10^-18 J. Then, λ = (6.626 × 10^-34 J∙s * 3.00 × 10^8 m/s) / 1.0112 × 10^-18 J ≈ 197 nm.

Quiz 28: Quantum Physics

A metallic surface is illuminated with light of wavelength 400 nm. If the work function for this metal is 2.40 eV, what is the maximum kinetic energy of the ejected electrons, in electron-volts? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

A laser pulse of duration 25 ms has a total energy of 1.4 J. If the wavelength of this radiation is 567 nm, how many photons are emitted in one pulse? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

For what wavelength does a 100-mW laser beam deliver 1.6 × 10¹⁷ photons in one second? (c = 3.0 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

A metal has a work function of 4.50 eV. Find the maximum kinetic energy of the photoelectrons if light of wavelength 250 nm shines on the metal. (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

Gamma rays are photons with very high energy. What is the wavelength of a gamma-ray photon with energy 7.7 × 10^-13 J? (c = 3.0 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

A laser emits a pulse of light that lasts 10 ns. The light has a wavelength of 690 nm, and each pulse has an energy of 480 mJ. How many photons are emitted in each pulse? (c = 3.0 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

An 84-kW AM radio station broadcasts at 1000 kHz. How many photons are emitted each second by the transmitting antenna? (h = 6.626 × 10^-34 J ? s)

A metal surface has a work function of 2.50 eV. What is the longest wavelength of light that will eject electrons from the surface of this metal? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

The work function of a particular metal is $4.20 \times 10 ^ { - 19 } \mathrm {~J}$ What is the photoelectric cutoff (threshold) wavelength for this metal? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

A helium-neon laser emits light at 632.8 nm. If the laser emits $1.82 \times 10 ^ { 17 }$ photons/second, what is its power output in mW? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

A crystal is irradiated with x-rays with a wavelength of 0.120 nm. The atomic planes in the crystal are separated by 0.21 nm. At what angles of incidence with respect to the normal will the x-rays reflect from the crystal?

If the longest wavelength of light that is able to dislodge electrons from a metal is 373 nm, what is the work function of that metal, in electron-volts? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

A photoelectric surface has a work function of 2.10 eV. Calculate the maximum kinetic energy, in eV, of electrons ejected from this surface by electromagnetic radiation of wavelength 356 nm. (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

What is the cutoff (threshold) frequency for a metal surface that has a work function of 5.42 eV? (1 eV = 1.60 × 10^-19 J, h = 6.626 × 10^-34 J ? s)

The work function of a certain metal is 1.90 eV. What is the longest wavelength of light that can cause photoelectron emission from this metal? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

Gamma rays are photons with very high energy. How many visible-light photons with a wavelength of 500 nm would you need to equal the energy of a gamma-ray photon with energy $4.1 \times 10 ^ { - 13 } \mathrm {~J} ?$

What is the longest wavelength of light that can cause photoelectron emission from a metal that has a work function of 2.20 eV? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

The lattice spacing of the principal Bragg planes in sodium chloride is 0.282 nm. For what wavelength of x-rays will the first order reflected beam diffract at 55° with respect to the normal to the crystal planes?

What is the wavelength of a 6.32-eV photon? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s, 1 eV = 1.60 × 10^-19J)

Quiz 28: Quantum Physics

A metallic surface is illuminated with light of wavelength 400 nm. If the work function for this metal is 2.40 eV, what is the maximum kinetic energy of the ejected electrons, in electron-volts? (1 eV = 1.60 × 10-19 J, c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ? s)

A laser pulse of duration 25 ms has a total energy of 1.4 J. If the wavelength of this radiation is 567 nm, how many photons are emitted in one pulse? (c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ∙ s)

For what wavelength does a 100-mW laser beam deliver 1.6 × 1017 photons in one second? (c = 3.0 × 108 m/s, h = 6.626 × 10-34 J ∙ s)

A metal has a work function of 4.50 eV. Find the maximum kinetic energy of the photoelectrons if light of wavelength 250 nm shines on the metal. (1 eV = 1.60 × 10-19 J, c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ∙ s)

Gamma rays are photons with very high energy. What is the wavelength of a gamma-ray photon with energy 7.7 × 10-13 J? (c = 3.0 × 108 m/s, h = 6.626 × 10-34 J ∙ s)

A laser emits a pulse of light that lasts 10 ns. The light has a wavelength of 690 nm, and each pulse has an energy of 480 mJ. How many photons are emitted in each pulse? (c = 3.0 × 108 m/s, h = 6.626 × 10-34 J ? s)

An 84-kW AM radio station broadcasts at 1000 kHz. How many photons are emitted each second by the transmitting antenna? (h = 6.626 × 10-34 J ? s)

A metal surface has a work function of 2.50 eV. What is the longest wavelength of light that will eject electrons from the surface of this metal? (1 eV = 1.60 × 10-19 J, c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ? s)

The work function of a particular metal is 4.20×10−19 J4.20 \times 10 ^ { - 19 } \mathrm {~J}4.20×10−19 J What is the photoelectric cutoff (threshold) wavelength for this metal? (c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ? s)

A helium-neon laser emits light at 632.8 nm. If the laser emits 1.82×10171.82 \times 10 ^ { 17 }1.82×1017 photons/second, what is its power output in mW? (c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ? s)

A crystal is irradiated with x-rays with a wavelength of 0.120 nm. The atomic planes in the crystal are separated by 0.21 nm. At what angles of incidence with respect to the normal will the x-rays reflect from the crystal?

If the longest wavelength of light that is able to dislodge electrons from a metal is 373 nm, what is the work function of that metal, in electron-volts? (1 eV = 1.60 × 10-19 J, c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ? s)

A photoelectric surface has a work function of 2.10 eV. Calculate the maximum kinetic energy, in eV, of electrons ejected from this surface by electromagnetic radiation of wavelength 356 nm. (1 eV = 1.60 × 10-19 J, c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ? s)

What is the cutoff (threshold) frequency for a metal surface that has a work function of 5.42 eV? (1 eV = 1.60 × 10-19 J, h = 6.626 × 10-34 J ? s)

The work function of a certain metal is 1.90 eV. What is the longest wavelength of light that can cause photoelectron emission from this metal? (1 eV = 1.60 × 10-19 J, c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ∙ s)

Gamma rays are photons with very high energy. How many visible-light photons with a wavelength of 500 nm would you need to equal the energy of a gamma-ray photon with energy 4.1×10−13 J?4.1 \times 10 ^ { - 13 } \mathrm {~J} ?4.1×10−13 J?

What is the longest wavelength of light that can cause photoelectron emission from a metal that has a work function of 2.20 eV? (1 eV = 1.60 × 10-19 J, c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ∙ s)

The lattice spacing of the principal Bragg planes in sodium chloride is 0.282 nm. For what wavelength of x-rays will the first order reflected beam diffract at 55° with respect to the normal to the crystal planes?

What is the wavelength of a 6.32-eV photon? (c = 3.00 × 108 m/s, h = 6.626 × 10-34 J ∙ s, 1 eV = 1.60 × 10-19 J)

A metallic surface is illuminated with light of wavelength 400 nm. If the work function for this metal is 2.40 eV, what is the maximum kinetic energy of the ejected electrons, in electron-volts? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

A laser pulse of duration 25 ms has a total energy of 1.4 J. If the wavelength of this radiation is 567 nm, how many photons are emitted in one pulse? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

For what wavelength does a 100-mW laser beam deliver 1.6 × 10¹⁷ photons in one second? (c = 3.0 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

A metal has a work function of 4.50 eV. Find the maximum kinetic energy of the photoelectrons if light of wavelength 250 nm shines on the metal. (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

Gamma rays are photons with very high energy. What is the wavelength of a gamma-ray photon with energy 7.7 × 10^-13 J? (c = 3.0 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

A laser emits a pulse of light that lasts 10 ns. The light has a wavelength of 690 nm, and each pulse has an energy of 480 mJ. How many photons are emitted in each pulse? (c = 3.0 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

An 84-kW AM radio station broadcasts at 1000 kHz. How many photons are emitted each second by the transmitting antenna? (h = 6.626 × 10^-34 J ? s)

A metal surface has a work function of 2.50 eV. What is the longest wavelength of light that will eject electrons from the surface of this metal? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

The work function of a particular metal is $4.20 \times 10 ^ { - 19 } \mathrm {~J}$ What is the photoelectric cutoff (threshold) wavelength for this metal? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

A helium-neon laser emits light at 632.8 nm. If the laser emits $1.82 \times 10 ^ { 17 }$ photons/second, what is its power output in mW? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

If the longest wavelength of light that is able to dislodge electrons from a metal is 373 nm, what is the work function of that metal, in electron-volts? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

A photoelectric surface has a work function of 2.10 eV. Calculate the maximum kinetic energy, in eV, of electrons ejected from this surface by electromagnetic radiation of wavelength 356 nm. (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s)

What is the cutoff (threshold) frequency for a metal surface that has a work function of 5.42 eV? (1 eV = 1.60 × 10^-19 J, h = 6.626 × 10^-34 J ? s)

The work function of a certain metal is 1.90 eV. What is the longest wavelength of light that can cause photoelectron emission from this metal? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

Gamma rays are photons with very high energy. How many visible-light photons with a wavelength of 500 nm would you need to equal the energy of a gamma-ray photon with energy $4.1 \times 10 ^ { - 13 } \mathrm {~J} ?$

What is the longest wavelength of light that can cause photoelectron emission from a metal that has a work function of 2.20 eV? (1 eV = 1.60 × 10^-19 J, c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s)

What is the wavelength of a 6.32-eV photon? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s, 1 eV = 1.60 × 10^-19J)