The period of an oscillating weight on a spring in an inertial frame of reference is 0.80 s. What would be its speed if it were to move by an observer who measures its period as 1.2 s? (c = 3.00 * 10⁸ m/s) A) 2.5 * l0⁸ m/s B) 1.1* l0⁸m/s C) 2.9 * 10⁸ m/s D) 2.2 *10⁸ m/s

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Quizplus · Accepted Answer

The time dilation formula is used here: T' = T / sqrt(1 - v^2/c^2). Solving for v when T' = 1.2 s and T = 0.8 s gives v ≈ 2.2 x 10^8 m/s.

The Period of an Oscillating Weight on a Spring in an Inertial