If a cordless phone operates at a frequency of 9.00 × 10⁸ s^-1,what is the wavelength of this radiation? A) 0.333 m B) 1.99 m C) 3.33 × 10^-9 m D) 3.71 × 10^-18 m E) 2.70 × 10¹⁷ m

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Quizplus · Accepted Answer

The frequency of the cordless phone is given as $9.00 \times 10^{18}$ Hz. To find the wavelength ($\lambda$) of this radiation, we use the equation $c = \lambda \nu$, where $c$ is the speed of light ($3.00 \times 10^8$ m/s) and $\nu$ is the frequency. Rearranging for $\lambda$, we get $\lambda = \frac{c}{\nu}$. Substituting the given values, $\lambda = \frac{3.00 \times 10^8 \text{ m/s}}{9.00 \times 10^{18} \text{ Hz}}$, which simplifies to approximately $0.333$ meters.

If a Cordless Phone Operates at a Frequency of 9