What is the energy per mole of photons of light with a frequency of 9.01 × 10¹⁴ Hz? A) 2.21 × 10^-31 kJ/mol B) 3.6 × 10² kJ/mol C) 2 × 10²³ kJ/mol D) 1.33 × 10^-10 kJ/mol E) 3.33 × 10² kJ/mol

Question

Quizplus · Accepted Answer

The energy of a photon can be calculated using the equation E = hf, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon. 
Plugging in the given frequency, we get: 
E = (6.626 x 10^-34 J*s)(9.01 x 10^14 Hz) = 5.97 x 10^-19 J per photon 
To convert this to energy per mole, we multiply by Avogadro's number (6.022 x 10^23) and divide by 1000 to convert from joules to kilojoules: 
(5.97 x 10^-19 J/photon)(6.022 x 10^23 photons/mol)/1000 = 3.6 x 10^12 kJ/mol 
Therefore, the answer is B.

What Is the Energy Per Mole of Photons of Light