How many moles of CH₃CH₂OH are contained in 548 mL of a 0.0788 mol L^-1 CH₃CH₂OH solution? A) 4.32 × 10^-2 mol B) 2.32 × 10^-2 mol C) 6.95 × 10^-2 mol D) 1.44 × 10^-2 mol E) 5.26 × 10^-2 mol

Question

Quizplus · Accepted Answer

To find the number of moles, use the formula: moles = concentration (mol/L) × volume (L). Convert 548 mL to liters (0.548 L) and multiply by 0.0788 mol/L to get 4.32 × 10^-2 mol.

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How Many Moles of CH₃CH₂OH Are Contained in 548 ML