According to the following reaction, what amount of Al₂S₃ remains when 20.00 g of Al₂S₃ and 2.00 g of H₂O are reacted? A few of the molar masses are as follows:
Al₂S₃= 150.17 g mol^-1, H₂O = 18.02 g mol^-1. Al₂S₃(s) + 6H₂O(l) → 2Al(OH) ₃(s) + 3H₂S(g)

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The Answer of According to the following reaction, what amount of Al₂S₃ remains when 20.00 g of Al₂S₃ and 2.00 g of H₂O are reacted? A few of the molar masses are as follows: Al₂S₃= 150.17 g mol^-1, H₂O = 18.02 g mol^-1. Al₂S₃(s) + 6H₂O(l) → 2Al(OH)₃(s) + 3H₂S(g) A) 28.33 g B) 14.00 g C) 8.33 g D) 19.78 g E) 17.22 g

According to the Following Reaction, What Amount of Al2S3 Remains

According to the Following Reaction, What Amount of Al₂S₃ Remains