A car moving initially at 30 m/s comes gradually to a stop in 900 m. What was the acceleration of the car? A) -0.5 m/s². B) -5 m/s². C) -10 m/s². D) -20 m/s².

Question

Quizplus · Accepted Answer

The acceleration can be found using the equation $v^2 = u^2 + 2as$, where $v$ is the final velocity (0 m/s), $u$ is the initial velocity (30 m/s), $a$ is the acceleration, and $s$ is the distance (900 m). Rearranging for $a$, we get $a = \frac{v^2 - u^2}{2s} = \frac{0^2 - 30^2}{2 \times 900} = \frac{-900}{1800} = -0.5 \, m/s^2$.

A Car Moving Initially at 30 M/s Comes Gradually to a Stop