A Methods and Measurement Analyst wants to develop a time standard for a certain task.In a preliminary study,he observed one employee perform the task six times with an average of 20 seconds and a standard deviation of 2 seconds. What is the normal time (NT)for this task if the employee worked at a twenty percent faster pace than is average?
A)4 seconds
B)16.7 seconds
C)20 seconds
D)24 seconds
E)100 seconds

Question

Quizplus · Accepted Answer

First, we need to calculate the standard time (ST) using the following formula:

ST = average time + (k x standard deviation)

where k is a constant based on the desired level of confidence. For a 95% confidence level, k is 1.96.

ST = 20 + (1.96 x 2) = 24.92 seconds

Next, we can calculate the normal time (NT) by adjusting for the faster pace of the employee:

NT = ST / (1 + percentage improvement)

NT = 24.92 / (1 + 0.20) = 20.77 seconds

Therefore, the best choice is D, with a normal time of 24 seconds.

A Methods and Measurement Analyst Wants to Develop a Time