What is the theoretical yield of chromium that can be produced by the reaction of 40.0 g of Cr₂O₃ with 8.00 g of aluminum according to the chemical equation below? 2Al + Cr₂O₃ → Al₂O₃ + 2Cr A) 7.7 g B) 15.4 g C) 27.4 g D) 30.8 g E) 49.9 g

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The limiting reactant is Cr₂O₃. The molar mass of Cr₂O₃ is 151.99 g/mol, so 40.0 g is 0.263 mol. According to the balanced equation, 1 mol of Cr₂O₃ produces 2 mol of Cr. Therefore, 0.263 mol of Cr₂O₃ produces 0.526 mol of Cr. The molar mass of Cr is 51.996 g/mol, so the theoretical yield is 0.526 mol × 51.996 g/mol = 27.4 g.

What Is the Theoretical Yield of Chromium That Can Be