How many grams are present in 0.885 moles of manganese?
A) 62.1 g
B) 48.6 g
C) 21.5 g
D) 27.5 g
E) 0.016 g

Name: How many grams are present in 0.885 moles of manganese? A) 62.1 g B) 48.6 g C) 21.5 g D) 27.5 g E) 0.016 g
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Question

Quizplus · Accepted Answer

To convert moles of manganese to grams, we need the molar mass of manganese:

Molar mass of Mn = 54.94 g/mol

Now we can use the formula:

grams = moles x molar mass

grams = 0.885 mol x 54.94 g/mol

grams = 48.56 g

Therefore, the answer is B) 48.6 g.

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