A system expands from a volume of 1.00 L to 2.00 L against a constant external pressure of 1.00 atm.What is the work (W)done by the system? (1 L·atm = 101.3 J) A)1.00 J B)2.00 J C)1.01 × 10² J D)1.01 × 10⁵ J E)3.00 J

Question

Quizplus · Accepted Answer

The work done by the system can be calculated using the formula: 
W = -PΔV
Where P is the external pressure and ΔV is the change in volume of the system. 
Substituting the given values, we get: 
W = -1.00 atm x (2.00 L - 1.00 L) 
W = -1.00 atm x 1.00 L 
W = -1.00 L·atm

Since the answer choices are given in joules, we need to convert the units using the given conversion factor:
1 L·atm = 101.3 J

W = (-1.00 L·atm) x (101.3 J/L·atm) 
W = -101.3 J

But the question asks for the magnitude of the work done, so we take the absolute value: 
|W| = 101.3 J

Therefore, the answer is: 
C) 1.01 × 10¹² J (in scientific notation) or 101.3 J (in standard notation)

A System Expands from a Volume of 1