What is the volume of NH₃ produced in the following reaction when 3.0 L of N₂ reacts with 4.0 L of H₂ ? N₂(g) + 3H₂(g) → 2NH₃(g) A) 1.5 L B) 2.7 L C) 6.0 L D) 7.5 L E) 12 L

Question

Quizplus · Accepted Answer

The reaction shows that 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃. Given the volumes of reactants (3.0 L of N₂ and 4.0 L of H₂), H₂ is the limiting reactant. Since 4.0 L of H₂ would react completely with 4/3 L of N₂ to produce 2*(4/3) = 8/3 L = 2.7 L of NH₃, following the stoichiometry of the reaction.

What Is the Volume of NH3 Produced in the Following

What Is the Volume of NH₃ Produced in the Following