What is the pressure in atmospheres exerted by a column of water that is 12.5 m high? (density of water = 1.00g/cm³; gravitational constant = 9.80665 m/s², 1 atm = 101,325 Pa = 760 torr = 760 mmHg) A) 123 atm B) 1.23 × 10⁵ atm C) 0.785 atm D) 1.21 atm E) 1.23 × 10^-3 atm

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To find the pressure exerted by a column of water, use the formula P = ρgh, where ρ is the density of water (1000 kg/m³, converting from 1.00 g/cm³), g is the acceleration due to gravity (9.80665 m/s²), and h is the height of the water column (12.5 m). Substituting these values gives P = 1000 kg/m³ * 9.80665 m/s² * 12.5 m = 122583.125 Pa. Converting this to atmospheres (since 1 atm = 101325 Pa), P = 122583.125 Pa / 101325 Pa/atm ≈ 1.21 atm.

What Is the Pressure in Atmospheres Exerted by a Column