What is the molarity of a solution of 10.0% by mass cadmium sulfate, CdSO₄ (208.47 g/mol)? The density of the solution is 1.10 g/mL. A) 0.528 M B) 0.436 M C) 0.479 M D) 0.100 M E) 1.89 M

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Quizplus · Accepted Answer

To find the molarity of the solution, we first determine the mass of cadmium sulfate in 1000 mL (or 1 L) of solution, since molarity is moles of solute per liter of solution. With a 10.0% by mass solution and a density of 1.10 g/mL, the mass of the solution per liter is 1100 g. Therefore, the mass of cadmium sulfate in this volume is 10.0% of 1100 g, which is 110 g. The molar mass of cadmium sulfate (CdSO4) is approximately 208.47 g/mol, so the number of moles of cadmium sulfate in 110 g is 110 g / 208.47 g/mol = 0.528 mol. Thus, the molarity of the solution is 0.528 M.

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