What is the molarity of a 17.0% by mass solution of sodium acetate, NaC₂H₃O₂ (82.0 g/mol), in water? The density of the solution is 1.09 g/mL. A) 0.170 M B) 0.207 M C) 2.07 M D) 2.26 M E) 1.90 M

Question

Quizplus · Accepted Answer

To find the molarity of the solution, we first need to find the moles of sodium acetate present in 1 L of the solution.

Mass of NaC2H3O2 in 1 L of solution = (17.0% by mass) x (1.09 g/mL) x (1000 mL/L) = 186.53 g
Number of moles of NaC2H3O2 = (mass/molar mass) = 186.53 g / 82.0 g/mol = 2.275 mol

Therefore, the molarity of the solution is:

Molarity = number of moles / volume in liters = 2.275 mol/L

Answer: D) 2.26 M

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