What is the percent CdSO₄ by mass in a 1.00 molal aqueous CdSO₄ solution? A) 0.001% B) 0.10% C) 17.2% D) 20.8% E) 24.4%

Question

Quizplus · Accepted Answer

To find the percent mass of CdSO₄ in a 1.00 molal solution, we need to first calculate the mass of CdSO₄ present in 1 kg of the solution. 1.00 molal means that there is 1 mole of CdSO₄ in 1000 g (1 kg) of water. The molecular weight of CdSO₄ is approximately 360 g/mol. Therefore, in 1 kg of water, there are: 1 mol CdSO₄ x 360 g/mol = 360 g CdSO₄ So, the mass percent of CdSO₄ in the solution is: (360 g CdSO₄ / 1000 g solution) x 100% = 36% However, we need to be careful because the question asks for the percent mass of CdSO₄ by mass, not by solution. So, we need to divide the mass of CdSO₄ by the total mass of the solution: (360 g CdSO₄ / (360 g CdSO₄ + 1000 g water)) x 100% ≈ 17.2% Therefore, the answer is C) 17.2%.

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