What is the pH of a 0.20 M solution of NH₄Cl? [K_b(NH₃)= 1.8 × 10^-⁵] A)3.74 B)4.98 C)6.53 D)9.02 E)11.28

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Quizplus · Accepted Answer

NH₄Cl is a salt of a weak base (NH₃) and a strong acid (HCl). In solution, NH₄⁺ acts as a weak acid. The pH can be calculated using the formula pH = 1/2(pKa - log C), where pKa = 14 - pKb. Substituting the given values, pKa = 14 - (-log(1.8 × 10⁻⁵)) = 9.26. Therefore, pH = 1/2(9.26 - log(0.20)) ≈ 4.98.

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