Find an equation of the circle that satisfies the given conditions. Center at the origin and passes through (5, 1)

Question

Quizplus · Accepted Answer

The equation of a circle with center at the origin and radius $r$ is $x^2+y^2=r^2$. Since the center is at the origin, the equation becomes $x^2+y^2=r^2$. The circle passes through the point $(5,1)$, so $5^2+1^2=r^2$. Solving for $r$ gives $r=\sqrt{26}$. Thus, the equation of the circle is $x^2+y^2=26$. This matches answer choice B.

Find an Equation of the Circle That Satisfies the Given