Given this frequency distribution, the random number 0.9015 would be interpreted as a demand of:
$$\begin{array} { | c | c | }
\hline \text { Demand } & \text { Frequency } \
\hline 0 & 38 \
\hline 1 & 22 \
\hline 2 & 22 \
\hline 3 & 18 \
\hline
\end{array}$$
A) 0.
B) 1.
C) 2.
D) 3.
E) 1 or 2.

Question

Given this frequency distribution, the random number 0.9015 would be interpreted as a demand of:
$$\begin{array} { | c | c | } 
\hline \text { Demand } & \text { Frequency } \
\hline 0 & 38 \
\hline 1 & 22 \
\hline 2 & 22 \
\hline 3 & 18 \
\hline
\end{array}$$
A) 0.
B) 1.
C) 2.
D) 3.
E) 1 or 2.

Quizplus · Accepted Answer

To interpret the random number 0.9015 as a demand, we first need to convert the frequencies into cumulative probabilities. The total frequency is $38 + 22 + 22 + 18 = 100$. The cumulative probabilities are:- Demand 0: $38/100 = 0.38$- Demand 1: $38/100 + 22/100 = 0.60$- Demand 2: $60/100 + 22/100 = 0.82$- Demand 3: $82/100 + 18/100 = 1.00$The random number 0.9015 falls between 0.82 and 1.00, which corresponds to a demand of 3.

Given This Frequency Distribution, the Random Number 0 A) 0 B) 1

Given This Frequency Distribution, the Random Number 0 A) 0
B) 1