A simple random sample of 100 bags of tortilla chips produced by Company X is selected every hour for quality control.In the current sample,18 bags had more chips (measured in weight)than the labeled quantity.The quality control inspector wishes to use this information to calculate a 90% confidence interval for the true proportion of bags of tortilla chips that contain more than the label states.What is the value of the standard error of ?
A)0.0015
B)0.038
C)0.063
D)0.384

Question

A simple random sample of 100 bags of tortilla chips produced by Company X is selected every hour for quality control.In the current sample,18 bags had more chips (measured in weight)than the labeled quantity.The quality control inspector wishes to use this information to calculate a 90% confidence interval for the true proportion of bags of tortilla chips that contain more than the label states.What is the value of the standard error of  ?
A)0.0015 
B)0.038 
C)0.063 
D)0.384

Quizplus · Accepted Answer

The formula for the standard error of a proportion is:

SE = sqrt[(p-hat * (1-p-hat)) / n]

where p-hat is the sample proportion, and n is the sample size.

In this case, the sample proportion is:

p-hat = 18/100 = 0.18

And the sample size is n = 100.

Plugging in these values, we get:

SE = sqrt[(0.18 * (1-0.18)) / 100] = 0.038

Therefore, the standard error is 0.038, which corresponds to answer choice B.

A Simple Random Sample of 100 Bags of Tortilla Chips