Visible light, with a frequency of 6.0 *10¹⁴ Hz, is reflected from a spaceship moving directly away at a speed of 0.90c.The frequency of the reflected waves observed at the source is: A)3.2 *10¹³ Hz B)1.4 * 10¹⁴ Hz C)6.0*10¹⁴ Hz D)2.6 * 10¹⁵ Hz E)1.1 *10¹⁶ Hz

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Quizplus · Accepted Answer

The frequency of the reflected waves observed at the source can be calculated using the Doppler effect formula for light. Given the spaceship is moving away at a speed of $0.90c$, the observed frequency ($f'$) will decrease. The formula for the observed frequency when the source is moving away is $f' = f \times \frac{1}{1 + \frac{v}{c}}$, where $f$ is the original frequency, $v$ is the velocity of the spaceship, and $c$ is the speed of light. Substituting the given values, the observed frequency decreases, which matches closest to the value given in option A.

Visible Light, with a Frequency of 6