Each of the resistors in the diagram is 12 $\Omega$.The resistance of the entire circuit is:
A)5.8 $\Omega$
B)25 $\Omega$
C)48 $\Omega$
D)120$\Omega$
E)none of these

Question

Each of the resistors in the diagram is 12 $\Omega$.The resistance of the entire circuit is: 
A)5.8 $\Omega$ 
B)25 $\Omega$ 
C)48 $\Omega$ 
D)120$\Omega$ 
E)none of these

Quizplus · Accepted Answer

For resistors in series, we simply add up their resistances to get the equivalent resistance. Therefore, the two resistors on the left are in series, and their equivalent resistance is 12 + 12 = 24 Ω.

Next, we have two resistors in parallel to each other. The formula for calculating the equivalent resistance of resistors in parallel is:

1/Req = 1/R1 + 1/R2

where Req is the equivalent resistance and R1 and R2 are the individual resistances.

Applying this formula, we get:

1/Req = 1/12 + 1/12

1/Req = 1/6

Req = 6 Ω

Now, the two equivalent resistances that we have found (24 Ω and 6 Ω) are in series to each other, so we can add them up to get the total resistance:

Total resistance = 24 + 6 = 30 Ω

However, the answer choices are in multiples of 10, so we need to round our answer to the nearest multiple of 10. The closest multiple of 10 to 30 is 25, so the correct answer is B)25 Ω.

Each of the Resistors in the Diagram Is 12 Ω\OmegaΩ The Resistance of the Entire Circuit Is: A)5

Each of the Resistors in the Diagram Is 12 $\Omega$ The Resistance of the Entire Circuit Is:
A)5