A force of 5 N stretches an elastic band at room temperature.The rate at which its entropy changes as it stretches is about: A)-2 x 10^-2 J/K·m B)2 x 10^-2 J/K·m C)1500 J/K·m D)-1500 J/K·m E)cannot be calculated without knowing the heat capacity

Question

Quizplus · Accepted Answer

The rate of change of entropy with respect to length is given by the negative of the force divided by the temperature. In this case, the force is 5 N and the temperature is room temperature, which is about 293 K. Therefore, the rate of change of entropy is about -5 N / 293 K = -2 x 10^-2 J/K·m.

A Force of 5 N Stretches an Elastic Band at Room