One end of a cylindrical pipe has a radius of 1.5 cm.Water (density = 1.0 x10³ kg/m³)streams steadily out at 7.0 m/s.The volume flow rate is: A)4.9x 10^-3 m³/s B)2.5 m³/s C)4.9 m³/s D)7.0 m³/s E)48 m³/s

Question

Quizplus · Accepted Answer

The volume flow rate is given by the product of the cross-sectional area of the pipe and the speed of the water. The cross-sectional area of the pipe is given by the formula A = πr^2, where r is the radius of the pipe. The speed of the water is given as 7.0 m/s. Substituting these values into the formula for the volume flow rate, we get:Q = Av = πr^2v = π(1.5 cm)^2(7.0 m/s) = 4.9 × 10^-3 m^3/sTherefore, the correct answer is A.

One End of a Cylindrical Pipe Has a Radius of 1.5