A 6.0-kg particle moves to the right at 4.0 m/s as shown.The magnitude of its angular momentum about the point O is: A)0 kg∙m²/s B)288 kg∙m²/s C)144 kg∙m²/s D)24 kg∙m²/s E)249 kg∙m²/s

Question

Quizplus · Accepted Answer

The formula for angular momentum about a point O is given by L = r x p, where r is the distance from the point O to the particle, and p is the linear momentum of the particle. To find the angular momentum about point O, we need to find the perpendicular distance between the point O and the line along which the particle is moving. This is 0.6 m.

The linear momentum of the particle is given by p = mv = 6.0 kg x 4.0 m/s = 24 kg∙m/s.

Therefore, the angular momentum about point O is L = r x p = (0.6 m) x (24 kg∙m/s) = 14.4 kg∙m²/s = 144 kg∙m/s (in the direction perpendicular to the plane containing point O and the velocity vector). The correct answer is therefore (C).

A 60-Kg Particle Moves to the Right at 4