A projectile is fired over level ground with an initial velocity that has a vertical component of 20 m/s and a horizontal component of 30 m/s.Using g = 10 m/s², the distance from launching to landing points is: A)40 m B)60 m C)80 m D)120 m E)180 m

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Quizplus · Accepted Answer

The time of flight can be calculated using the vertical component of the initial velocity and the acceleration due to gravity. The time to reach the maximum height is $t = \frac{v_{vertical}}{g} = \frac{20 m/s}{10 m/s^2} = 2 s$. Since the motion to the maximum height and back down is symmetrical, the total time of flight is $2t = 4 s$. The horizontal distance covered in this time, using the horizontal component of the velocity, is $distance = v_{horizontal} \times time = 30 m/s \times 4 s = 120 m$.

A Projectile Is Fired Over Level Ground with an Initial