A compound is analyzed and found to contain 12.1% carbon, 16.2% oxygen, and 71.7% chlorine (by mass). Calculate the empirical formula of this compound.

Question

Quizplus · Accepted Answer

To find the empirical formula, convert the percentages to moles: C: 12.1 g/12.01 g/mol = 1.01 mol, O: 16.2 g/16.00 g/mol = 1.01 mol, Cl: 71.7 g/35.45 g/mol = 2.02 mol. The simplest ratio is 1:1:2, giving COCl₂.

A Compound Is Analyzed and Found to Contain 12