The specific heat capacity of iron is 0.45 J/g·°C. How many joules of energy are needed to warm 1.31 g of iron from 20.00°C to 29.00°C?
A) 17 J
B) 12 J
C) 26 J
D) 11 J
E) 5.3 J

Question

Quizplus · Accepted Answer

The energy required can be calculated using the formula $q = mc\Delta T$, where $q$ is the heat energy, $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T$ is the change in temperature. Plugging in the given values: $q = 1.31 \, \text{g} \times 0.45 \, \text{J/g}·°\text{C} \times (29.00°C - 20.00°C) = 5.2945 \, \text{J}$, which rounds to 5.3 J.

The Specific Heat Capacity of Iron Is 0