A sample of oxygen gas (O₂) has a volume of 7.08 L at a temperature of 19^oC and a pressure of 1.38 atm. Calculate the moles of O₂ molecules present in this gas sample. A) 6.27 mol B) 0.408 mol C) 0.816 mol D) 0.204 mol E) none of these

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Quizplus · Accepted Answer

To find the moles of $O_2$ gas, we can use the ideal gas law equation: $PV = nRT$, where $P$ is the pressure in atm, $V$ is the volume in liters, $n$ is the number of moles, $R$ is the ideal gas constant (0.0821 L·atm/(mol·K)), and $T$ is the temperature in Kelvin. Given $P = 1.38$ atm, $V = 7.08$ L, and $T = 19^\circ C = 292 K$, we can solve for $n$: $n = \frac{PV}{RT} = \frac{(1.38)(7.08)}{(0.0821)(292)} \approx 0.408$ mol.

A Sample of Oxygen Gas (O2) Has a Volume of 7.08

A Sample of Oxygen Gas (O₂) Has a Volume of 7.08