What is the normality of 1.00 L of a sodium hydroxide solution that contains 18.2 g of NaOH?
A) 2.20 N
B) 18.2 N
C) 0.228 N
D) 0.455 N
E) none of these

Question

Quizplus · Accepted Answer

Normality is calculated by dividing the equivalent weight of solute by the volume of solution in liters. The equivalent weight of NaOH is its molar mass (40 g/mol) since it provides one mole of OH- ions per mole of NaOH. Thus, 18.2 g of NaOH is 0.455 equivalents (18.2 g / 40 g/mol), and in 1.00 L, the normality is 0.455 N.

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