What volume of a 0.176 M Na₂S solution contains 1.01 g of Na⁺ ions? A) 0.250 L B) 8.01 L C) 4.01 L D) 0.425 L E) 0.125 L

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First, calculate the molar mass of NaS (Sodium Sulfide): Na = 22.99 g/mol, S = 32.06 g/mol, so NaS = 22.99 + 32.06 = 55.05 g/mol. Next, find the number of moles of NaS in 1.01 g: 1.01 g / 55.05 g/mol = 0.01835 mol. Since the concentration of the solution is 0.176 M (moles per liter), the volume of solution that contains 0.01835 mol is found by dividing the moles by the concentration: 0.01835 mol / 0.176 mol/L = 0.10426 L, which is approximately 0.125 L.

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