An RLC series circuit is driven by a sinusoidal emf with angular frequency $ \omega $_d. If $ \omega $_d is increased without changing the amplitude of the emf the current amplitude increases. If the L is inductance, C is the capacitance, and R is the resistance, this means that: A) $ \omega $_dL 1/ $ \omega $_dC B) $ \omega $_dL R E) $ \omega $_dL

Question

An RLC series circuit is driven by a sinusoidal emf with angular frequency $ \omega $_d. If $ \omega $_d is increased without changing the amplitude of the emf the current amplitude increases. If the L is inductance, C is the capacitance, and R is the resistance, this means that: A) $ \omega $_dL > 1/ $ \omega $_dC B) $ \omega $_dL < 1/ $ \omega $_dC C) $ \omega $_dL = 1/ $ \omega $_dC D) $ \omega $_dL > R E) $ \omega $_dL < R

Quizplus · Accepted Answer

The resonance frequency of an RLC circuit is given by 1/(2π√LC). As the angular frequency F1F1F1S1F1F1F10_d increases, the circuit moves away from the resonance frequency, causing the current amplitude to increase. This can happen only if the inductive reactance, which is proportional to the angular frequency multiplied by the inductance, is greater than the capacitive reactance, which is proportional to the inverse of the angular frequency multiplied by the capacitance. Therefore, F1F1F1S1F1F1F10_dL < 1/F1F1F1S1F1F1F10_dC.

An RLC Series Circuit Is Driven by a Sinusoidal Emf ω \omega ω

An RLC Series Circuit Is Driven by a Sinusoidal Emf $\omega$