Balance the reaction below in acidic solution.IO₃^- + I^- → I₂
What volume of 0.352 M HCl is needed to produce 2.48 × 10^-3 mol of iodine, I₂, with an excess of KIO₃ and KI?

Question

Quizplus · Accepted Answer

The balanced reaction in acidic solution is:IO₃^- + 5I^- + 6H⁺ → 3I₂ + 3H₂OTo produce 2.48 × 10^-3 mol of I₂, we need 5 times this amount of I^-, which is 1.24 × 10^-2 mol. Since the concentration of HCl is 0.352 M, we need 1.24 × 10^-2 mol / 0.352 M = 3.52 × 10^-2 L = 35.2 mL of HCl. Therefore, the correct answer is A) 14.1 mL.

Balance the Reaction Below in Acidic Solution