A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 × 10 -3 M CuNO 3 . Cu(I) forms complex ions with cyanide as follows: Calculate the following concentrations at equilibrium: -[Cu⁺] A) 2.0 × 10^-13 M B) 8.0 × 10^-15 M C) 1.6 × 10^-13 M D) 4.0 × 10^-13 M E) none of these

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The Answer of A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 × 10 -3 M CuNO 3 . Cu(I) forms complex ions with cyanide as follows: Calculate the following concentrations at equilibrium: -[Cu⁺] A) 2.0 × 10^-13 M B) 8.0 × 10^-15 M C) 1.6 × 10^-13 M D) 4.0 × 10^-13 M E) none of these

A Solution Is Formed by Mixing 50