A 50.0-mL sample of 2.0 × 10^-4 M CuNO₃ is added to 50.0 mL of 4.0 M NaCN. Cu⁺ reacts with CN^- to form the complex ion Cu(CN)₃^2-: What is the concentration of CN^- at equilibrium? A) 6.0 × 10^-4 M B) 1.0 M C) 4.0 M D) 2.0 M E) none of these

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The Answer of A 50.0-mL sample of 2.0 × 10^-4 M CuNO₃ is added to 50.0 mL of 4.0 M NaCN. Cu⁺ reacts with CN^- to form the complex ion Cu(CN)₃^2-: What is the concentration of CN^- at equilibrium? A) 6.0 × 10^-4 M B) 1.0 M C) 4.0 M D) 2.0 M E) none of these

A 500-ML Sample of 2