The process H 2 O(g) → H 2 O(l) takes place at 1 atm and 95°C.
-Calculate ΔS for cooling 2.60 mol of an ideal monatomic gas from 88°C to 39°C at constant volume.

Question

Quizplus · Accepted Answer

We can use the formula ΔS = nCv ln(T2/T1) where n is the number of moles, Cv is the molar heat capacity at constant volume, T1 is the initial temperature, and T2 is the final temperature.

Since the gas is ideal and monatomic, Cv = (3/2)R, where R is the gas constant. Plugging in the given values, we get:

ΔS = (2.60 mol)(3/2)(8.314 J/mol*K) ln(312 K/361 K)
ΔS = -4.73 J/K

Therefore, choice D is the correct answer.

The Process H2O(g) → H2O(l) Takes Place at 1 Atm

The Process H₂O(g) → H₂O(l) Takes Place at 1 Atm