If the change in entropy of the surroundings for a process at 443 K and constant pressure is -347 J/K, what is the heat flow absorbed by the system?

Question

Quizplus · Accepted Answer

The heat flow absorbed by the system is given by the equation:Q = -TΔSwhere Q is the heat flow, T is the temperature, and ΔS is the change in entropy.Substituting the given values into the equation, we get:Q = -(443 K)(-347 J/K) = 154 kJTherefore, the heat flow absorbed by the system is 154 kJ.

If the Change in Entropy of the Surroundings for a Process